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-   -   Question for al of you Computer Savvy Geniuses Out There (http://www.genmay.com/showthread.php?t=849278)

Dunkirk101 09-30-2016 03:29 PM

Question for al of you Computer Savvy Geniuses Out There
 
This is a question pertaining to basic internet protocol

For the slash ( / ) address 255.255.255.252 How many addresses are present?

growler 09-30-2016 05:36 PM

256

Dunkirk101 09-30-2016 05:49 PM

[QUOTE=growler;25518502]256[/QUOTE]

Please elaborate on how you achieved this answer

joemama 09-30-2016 06:17 PM

Correct answer in detail:

1. Open nearest window (or don't, makes no diff)
2. Unplug pc (or don't)
3. Toss pc out of previously opened or unopened window
4. Problem solved

Dunkirk101 10-01-2016 09:16 AM

[QUOTE=joemama;25518505]Correct answer in detail:

1. Open nearest window (or don't, makes no diff)
2. Unplug pc (or don't)
3. Toss pc out of previously opened or unopened window
4. Problem solved[/QUOTE]

Ha :rolleyes:

I have the answer now...

The slash CIDR or (Classless Inter Domain Routing) number would be indeed 30 (or /30), and withy only two host bits left, the host addresses would be 4

1) address 0 (Network)
2) address 1
3) address 2
4) address 3 (Broadcast)

0 is for Networking and cannot be used
3 is a Broadcast address and cannot be used

This only leaves 2 useable addresses left and would be mainly for used for Point to Point


YES.. I am Spartacus!! ;)

Typhoon43 10-03-2016 12:28 PM

Look out, we have ourselves a CCIE up in here :lol:


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