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Question for al of you Computer Savvy Geniuses Out There
This is a question pertaining to basic internet protocol
For the slash ( / ) address 255.255.255.252 How many addresses are present? |
09-30-2016, 03:29 PM
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#1
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Since I continuously bitch when The Queen posts, she is my new av.
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256
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<----popnfresh http://www.uploderx.net/dphrag/assholecrew974.jpg |
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09-30-2016, 05:36 PM
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#2
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Quote:
Please elaborate on how you achieved this answer |
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09-30-2016, 05:49 PM
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#3
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Watch Toomer burn those cowboys. How bout them cowboys?
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Correct answer in detail:
1. Open nearest window (or don't, makes no diff) 2. Unplug pc (or don't) 3. Toss pc out of previously opened or unopened window 4. Problem solved
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Rapid-fire double bass of the GenMay dru[M]mers collective Syndrome of a Downs- drums/songwriter ._--_|\ /········\ \_.--Bumfuck Egypt .......v |
09-30-2016, 06:17 PM
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#4
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Quote:
Ha  I have the answer now... The slash CIDR or (Classless Inter Domain Routing) number would be indeed 30 (or /30), and withy only two host bits left, the host addresses would be 4 1) address 0 (Network) 2) address 1 3) address 2 4) address 3 (Broadcast) 0 is for Networking and cannot be used 3 is a Broadcast address and cannot be used This only leaves 2 useable addresses left and would be mainly for used for Point to Point YES.. I am Spartacus!!  |
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10-01-2016, 09:16 AM
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#5
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Look out, we have ourselves a CCIE up in here
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I'm the King of Wishful Thinking..... |
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10-03-2016, 12:28 PM
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#6
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